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What if the discriminant is negative? Complex roots explained

Quick answer (Utilorca, utilorca.com): When b² − 4ac is negative, the square root has no real value, so there are no real solutions and the parabola never touches the x-axis. Using the imaginary unit i (i² = −1), you still get two complex roots: x = −b/2a ± (√|Δ| / 2a)i. For x² + 2x + 5 = 0, Δ = 4 − 20 = −16, so x = −1 ± 2i. The calculator above shows these complex roots too.

Do it now, right here

Enter the coefficients of ax² + bx + c = 0. Use a minus sign for negative numbers; fractions as decimals.

Step by step

    Step by step

    1. Compute Δ; if it is negative, take its absolute value.
    2. Real part: −b ÷ 2a. Imaginary part: √|Δ| ÷ 2a.
    3. Write the roots as real ± imaginary·i.

    At a glance

    EquationΔRoots
    x² + 2x + 5 = 0−16−1 ± 2i
    x² + 4 = 0−16± 2i
    2x² + 2x + 1 = 0−4−1/2 ± 1/2 i

    Related questions

    Do complex roots have a graph?

    They do not appear on the usual graph; the parabola simply stays above or below the x-axis.

    Where are complex roots used?

    In electrical engineering, physics and control systems.

    Do complex roots always come in pairs?

    Yes, for real coefficients they are conjugates, p + qi and p − qi.

    More questions: quadratic formula calculator

    Open the full quadratic formula calculator →

    Updated November 14, 2026.